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Annette [7]
3 years ago
11

(-2/3) -15.6 + (1/4 x -15.6)

Mathematics
2 answers:
borishaifa [10]3 years ago
6 0

Answer:

Step-by-step explanation:

\frac{-2}{3}-15.6+\frac{1}{4}x-15.6 = \frac{-2}{3}- 15.6 - 15.6 + \frac{1}{4}x\\\\ = \frac{-2}{3} - 31.2+\frac{1}{4}x\\\\= \frac{-2}{3}-\frac{31.2*3}{1*3}+\frac{1}{4}x\\\\= \frac{-2}{3}-\frac{93.6}{3}+\frac{1}{4}x\\\\= \frac{-95.6}{3}+\frac{1}{4}x

Ksivusya [100]3 years ago
4 0

Answer:

Video result for (-2/3) -15.6 + (1/4 x -15.6) negative two thirds times negative fifteen and six tenths plus one fourth times negative fifteen and six tenths. please help me.4:33

Multiplying positive and negative fractions (video)

Khan Academy · Khan Academy

Video result for (-2/3) -15.6 + (1/4 x -15.6) negative two thirds times negative fifteen and six tenths plus one fourth times negative fifteen and six tenths. please help me.4:11

Dividing negative fractions (video)

Khan Academy · Khan Academy

Video result for (-2/3) -15.6 + (1/4 x -15.6) negative two thirds times negative fifteen and six tenths plus one fourth times negative fifteen and six tenths. please help me.5:01

Subtracting fractions with unlike denominators (video)

Khan Academy · Khan Academy

Video result for (-2/3) -15.6 + (1/4 x -15.6) negative two thirds times negative fifteen and six tenths plus one fourth times negative fifteen and six tenths. please help me.6:22

Adding fractions with different signs (video)

Khan Academy · Khan Academy

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Step-by-step explanation:

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Answer:

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The p value for this case would be given by:

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For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

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Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:p \leq 0.42  

Alternative hypothesis:p > 0.42  

The statistic is given by:

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Replacing the info we got:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

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Answer:

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Step-by-step explanation:

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