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Allisa [31]
3 years ago
10

Which formulas and their respective names match?

Physics
2 answers:
coldgirl [10]3 years ago
6 0
1. Li3N lithium nitride
AND
3.SO2 sulfur dioxide
leonid [27]3 years ago
5 0

Answer:the correct options are: (i) and (iii)

Explanation:

The name of the molecule  Li_3N is lithium nitride.

The name of the molecule H_2S is hydrogen sulfide. The hydrogen sulfite is represented by molecular formula of  H_2SO_3.

The name of the molecule SO_2, is sulfur dioxide.Since, it is a covalent compound prefix will be used in front of an anions while writing the name of the this compound.

The name of the molecule is AlF_3 is aluminium fluorides. It is an ionic compound while writing its name no prefixes will used in front of an anions.

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If the work put into a lever is 25.0 joules and the work done by the lever is 20.0 joules, what is the efficiency of the lever?
Liula [17]
The efficiency is Wout/Win = 25/20
5 0
3 years ago
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How many joules of energy are required to accelerate one kilogram of mass from rest to a velocity of 0.866c?
Arlecino [84]

Answer:

the amount of energy needed is 1.8 x 10¹⁷ J.

Explanation:

Given;

mass of the object, m₀ = 1 kg

velocity of the object, v = 0.866 c

By physics convection, c is the speed of light = 3 x 10⁸ m/s

The energy needed is calculated as follows;

E = Mc²

As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\  M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg

The energy required is calculated as;

E = 2 x (3 x 10⁸)²

E = 1.8 x 10¹⁷ J

Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.

3 0
3 years ago
In Burglar alarm LDR acts as a/an<br> a. off switch<br> b. on switch<br> c. AND gate<br> d. OR gate
Gelneren [198K]

In Burglar alarm, LDR acts an AND gate.

Answer: C

Explanation

The LDR is light dependent resistor. The principle used in the working of LDR is that the resistance is inversely proportional to the intensity of light falling on the diode.

In burglar alarm, LDR diode is combined with an IC 555.

Normally an LED source is made to be incident on the LDR diode with same intensity such that the resistance will be maintained constant.

As the LDR is connected with IC, the voltage will be high when light is falling on the diode.

The IC will give only two output states that is high and low. This confirms that LDR in burglar alarm act as AND gate.

As the thief enters and crosses the LED light, the intensity of the light falling on the diode will decrease leading to decrease in the voltage which will cause the alarm to beep.

4 0
3 years ago
if you take one hour drive at an average speed of 65 mph, is it possible for another car with an average speed of 55 mph to pass
SVETLANKA909090 [29]
Nope, this is impossible because in order for a car to pass another, they the 55 mph car would have to be behind the 65 mph car (meaning that starting ahead of the 65 mph doesn't count as pass). Assuming that they both drive for one hour, it is impossible because the first will cover a distance of 65 mi and the second would cover a distance of 55 mi. One is obviously ahead of the other and is therefore impossible for the slow one to pass the first one unless the slow car keeps driving after an hour. In that case, it would take approximately 11 minutes for it to pass the other car. This was found by finding the distance needed to pass the first car : 65 - 55 = 10 mi and converted using 1 hr/ 55 mi = .18181818 hr x 60 min/ 1 hr = 11 seconds
I hope this helps :)
7 0
3 years ago
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From Gauss's law, the electric field set up by a uniform line of charge is given by the following expression where is a unit vec
Evgesh-ka [11]

Answer:

\Delta V=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})

Explanation:

Using the Gauss Law, we obtain the electric Field for a uniform large line of charge:

2\pi r L*E=\lambda *L/\epsilon_{o}

E=\lambda /\(2 \pi* r *\epsilon_{o})

We calculate the potential difference from the electric field:

\Delta V=-\int\limits^{r_{1}}_{r_{2}} E \, dr =-\int\limits^{r_{1}}_{r_{2}} \lambda dr/ (2\pi*r*\epsilon_{o})=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})

5 0
4 years ago
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