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2 years ago

What is the relationship between the voltage across the energy

Physics

2 answers:

Andrei [34K]2 years ago

8 0

Answer:

وؤتي يتنييوتينستصميوخصز ءتث. ثنصطث

STatiana [176]2 years ago

7 0

In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component. If two or more components are connected in parallel they have the same potential difference ( voltage) across their ends.

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A 535 kg roller coaster car began at rest at the top of a 93.0 m hill. Now it is at the top of the first loop-de-loop. This roll

Nikitich [7]

The correct answer is The car has both potential and kinetic energy, and it is moving at 24.6 m/s.

3 0

2 years ago

Use Hooke's Law, which states that the distance a spring stretches (or compresses) from its natural, or equilibrium, length vari

Phantasy [73]

Answer:

706.68 N

Explanation:

By Hooke's law,

$F = ke$

$k=\dfrac{F}{e}$

Using the values in the question,

$k=\dfrac{265\text{ N}}{0.15 \text{ m}}=1766.7\text{ N/m}$

When e = 0.4 m,

$F = 1766.7\text{ N/m}\times0.4\text{ m}=706.68\text{ N}$

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2 years ago

An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then

gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

$a=\frac{dv}{dt}=1.76$

So, the velocity can be obtained by integrating this expression:

$v=1.76t$

The velocity is, by definition: $v=\frac{dx}{dt}$ , so

$dx=1.76tdt\\x=1.76\frac{t^{2}}{2}$ .

Do x=11 in order to find the time spent.

$11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s$

At this time the velocity is: $v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}$

This velocity remains constant in the section 2, so for that section the movement equation is:

$x=v*t\\t=\frac{x}{v}$

The left distance is 89 meters, and the velocity is $6.2225\frac{m}{s}$ , so:

$t=\frac{89}{6.2225}=14.303s$

So, the total time is 14.303+3.5355s=17.838s

7 0

2 years ago

Two masses, each weighing 1.0 × 103 kilograms and moving with the same speed of 12.5 meters/second, are approaching each other.

juin [17]

A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. Therefore, we just add the kinetic energies of each system. We calculate as follows:

KE = 0.5(1.0 × 10^3)(12.5 )^2 + 0.5(1.0 × 10^3)(12.5 )^2
KE = 156250 J = 1.6 x 10^5 J -------> OPTION A

5 0

3 years ago

The route followed by a hiker consists of three displacement vectors A with arrow, B with arrow, and C with arrow. Vector A with

kotykmax [81]

Answer:

$D_{B}=1173.98m\\D_{C}=675.29m$