A collection of coins nickels and quarters is worth $1.25 . There are 13 coins in all. How many of each are there?

The price of a dress is reduced by 550%. When the dress still does not sell, it is reduced by 550% of the reduced price. If t

Masja [62]

Answer:

x = $200

The original price is $200

Question :

The price of a dress is reduced by 50%. When the dress still does not sell, it is reduced by 50% of the reduced price. If the price of the dress after both reductions is $50, what was the original price?

Step-by-step explanation:

Let x represent the original price of the dress.

First reduction

After first reduction the value of the price is given as;

p1 = x - 50% of x = (1-0.50)x = 0.5x

p1 = 0.5x

Second reduction

After the second reduction the value of the price is given as;

p2 = p1 - 50% of p1 = (1-0.50)p1 = (0.50)0.50x

p2 = 0.25x .....1

Since, p2 is given

p2 = $50

Substituting into equation 1

$50 = 0.25x

x = $50/0.25 = $200

x = $200

The original price is $200

4 0

3 years ago

Which measure is equivalent to 126 in. ? 1 ft = 12 in. 1 yd = 3 ft 3 yd 3. 5 yd 10. 5 yd 31. 5 yd.

denis23 [38]

Answer:

3.5 YARD

Step-by-step explanation:

3.5 x 3= 10.5x12= 126

6 0

1 year ago

What is 3.1 - 4.9(x + 1)

liq [111]

Answer:

-49x - 18 is the final answer!

5 0

3 years ago

Read 2 more answers

Assuming that a soap bubble is a perfect sphere, what is the diameter of a bubble containing 1,000 cm3 of air? Round to the near

Minchanka [31]

Answer:

17.85 cm

Step-by-step explanation:

1) Area of a sphere formula: $A=4\pi r^{2}$

2) Plug in A: 1000 = $4\pi r^{2}$

3) Simplify: 1000 = 12.56 $r^{2}$

4) Divide Each Side By 12.56: 79.61783439 = $r^{2}$

5) Take the Square Root of 79.61783439 to Solve for $r$ : 8.922882628 = $r$

6) Double $r$ to get the diameter: 8.922882628*2= 17.84576486

7) Round to the Nearest Tenth: 17.85 cm

8 0

3 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: