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labwork [276]
3 years ago
13

What is the x-intercepts of the graph of y = 12x-5x-2

Mathematics
2 answers:
hammer [34]3 years ago
8 0
Y = 12x - 5x - 2

first simplify the equation by subtracting like terms (in this case):

12x - 5x = 7x

y = 7x - 2

Since you are finding the x, you must isolate the x. Do the opposite of PEMDAS.(Note: because there is a equal sign, what you do to one side, you do to the other)

y = 7x - 2

y (+2) = 7x - 2 (+2)
y + 2 = 7x
(y + 2)/7 = 7x/7

x = (y + 2)/7


x = (y + 2)/7 is your answer

hope this helps
PilotLPTM [1.2K]3 years ago
6 0
X intercept = when the graph cuts the x-axis = when y = 0


y = 12x^2 -5x -2

when y = 0
12x^2 -5x -2 = 0
(3x - 2) (4x + 1) = 0
x = 2/3 or x = 1/4

So the x-intercept are (2/3, 0) and (1/4, 0)

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8 0
3 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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tigry1 [53]

Answer:

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Step-by-step explanation:

Use PEMDAS

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