Question

Rosa says she can break this array(6 rows,8 in each row) into 3 different sets of two smaller arrays.Is Rosa correct.Explain

Answer 1

Answer:

Rosa is correct

Step-by-step explanation:

Rosa has array $6 \times 8$ (6 rows and 8 columns). She can break this array into two smaller arrays in such ways:

• 1st array $5\times 8$ (5 rows and 8 columns) and 2nd array $1\times 8$ (1 row and 8 columns);
• 1st array $4\times 8$ (4 rows and 8 columns) and 2nd array $2\times 8$ (2 rows and 8 columns);
• 1st array $3\times 8$ (3 rows and 8 columns) and 2nd array $3\times 8$ (3 rows and 8 columns);
• 1st array $6\times 1$ (6 rows and 1 column) and 2nd array $6\times 7$ (6 rows and 7 columns);
• 1st array $6\times 2$ (6 rows and 2 columns) and 2nd array $6\times 6$ (6 rows and 6 columns);
• 1st array $6\times 3$ (6 rows and 3 columns) and 2nd array $6\times 5$ (6 rows and 5 columns);
• 1st array $6\times 4$ (6 rows and 4 columns) and 2nd array $6\times 4$ (6 rows and 4 columns).

So, there are even more than 3 different ways.