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katrin [286]
3 years ago
11

When finding the product (x – 3)(x + 4), what would you add to get the final answer?

Mathematics
1 answer:
kotykmax [81]3 years ago
6 0
When multiplying out you get:

x2+4x-3x-12....

so you'd be adding the +4x to the -3x

x2 + x - 12
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Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°
natima [27]

 

\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0

.

\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

5 0
3 years ago
In ΔDEF, e = 2.7 inches, ∠F=49° and ∠D=58°. Find the length of f, to the nearest 10th of an inch.
Anton [14]

Answer:2.1

Step-by-step explanation:

\text{Draw a diagram:}

Draw a diagram:

D

E

F

e = 2.7

f = ?

49°

58°

\text{A.S.A.}\rightarrow \text{Law of Sines}

A.S.A.→Law of Sines

\frac{a}{\sin A}=\frac{b}{\sin B}

sinA

a

​

=

sinB

b

​

\text{Find other angle:}

Find other angle:

\angle E=180-49-58=73^{\circ}

∠E=180−49−58=73

∘

D

E

F

e = 2.7

f = ?

49°

58°

73°

\frac{f}{\sin 49}=\frac{2.7}{\sin 73}

sin49

f

​

=

sin73

2.7

​

f=\frac{2.7\sin 49}{\sin 73} \approx 2.131 \approx 2.1

f=

sin73

2.7sin49

​

≈2.131≈2.1

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Answer:

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