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drek231 [11]
3 years ago
14

Write the expressions that represents 7 subtracted from 8n

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0
8n - 7
because from 8n, 7 is subtracted

poizon [28]3 years ago
5 0

Answer:

The answer is 8n - 7

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Are these ratios equivalent?
lianna [129]

Answer:

Yes

Step-by-step explanation:

3:9 in their lowest forms are 1:3 which is the same for 6:18

5 0
3 years ago
If the point A is located at (-5,-3) and A’ is the image of A after being rotated about the origin by 270 (counter clockwise). W
Rom4ik [11]

Answer:

D (-3, 5)

Step-by-step explanation:

270 counter clockwise is the same as 90 clockwise.

For a 90° clockwise or 270° counter clockwise, take the opposite of the x coordinate then switch the coordinates.

(-5, -3) -----> (5, -3) ------> (-3, 5)

You can also rotate your screen 90° clockwise to see the new coordinates for A.

3 0
2 years ago
Equation that represents the line that passes through the point (-2,-1) and has a slope of 5
ss7ja [257]
Straight line:
y = mx + c
m is the slope of the graph and c is the y-intercept
In this case, m = 5 as stated in the question, so...
y = 5x + c
By substituting the given co-ordinates (-2,-1) into this equation, we can find c
-1 = 5(-2) + c
-1 = -10 + c
-1 + 10 = -10 + c + 10 (Add 10 to both sides)
9 = c
c = 9
Put c = 9 into the equation:
y = 5x + 9
5 0
3 years ago
How to solve this trigonometric equation cos3x + sin5x = 0
mrs_skeptik [129]

Answer:

  x = {nπ -π/4, (4nπ -π)/16}

Step-by-step explanation:

It can be helpful to make use of the identities for angle sums and differences to rewrite the sum:

  cos(3x) +sin(5x) = cos(4x -x) +sin(4x +x)

  = cos(4x)cos(x) +sin(4x)sin(x) +sin(4x)cos(x) +cos(4x)sin(x)

  = sin(x)(sin(4x) +cos(4x)) +cos(x)(sin(4x) +cos(4x))

  = (sin(x) +cos(x))·(sin(4x) +cos(4x))

Each of the sums in this product is of the same form, so each can be simplified using the identity ...

  sin(x) +cos(x) = √2·sin(x +π/4)

Then the given equation can be rewritten as ...

  cos(3x) +sin(5x) = 0

  2·sin(x +π/4)·sin(4x +π/4) = 0

Of course sin(x) = 0 for x = n·π, so these factors are zero when ...

  sin(x +π/4) = 0   ⇒   x = nπ -π/4

  sin(4x +π/4) = 0   ⇒   x = (nπ -π/4)/4 = (4nπ -π)/16

The solutions are ...

  x ∈ {(n-1)π/4, (4n-1)π/16} . . . . . for any integer n

5 0
3 years ago
Is (2, 10) a solution to this system of inequalities?<br> y y &gt; 4x + 1<br> yes<br> no
velikii [3]

Answer:

yes

Step-by-step explanation:

6 0
2 years ago
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