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3 years ago

Please help me i really need help please

Mathematics

1 answer:

Digiron [165]3 years ago

6 0

Answer:

its C I have study abt it so donot worry it's c

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On a piece of paper, use a protractor to construct right triangle DEF with DE=4 in. , m∠D=90° , and m∠E=45° . What statement is

Makovka662 [10]

I think the second one hope this helps

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3 years ago

What happens after coral is bleached?

attashe74 [19]

Answer: B

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2 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

Help i dont know what it is if i get one more wrong i dont pass the level

Semenov [28]

Answer:

blue and green because parallel means two lines that will never cross

3 0

3 years ago

What is the area of the rectangular piece of wood?

Mama L [17]

Answer:

2x^2 + 7x + 3 is the area of the rectangular piece of wood.

Step-by-step explanation:

Here,

Length ( l ) = x + 3

Breadth ( b ) = 2x + 1

Formula : -

Ar ( rectangle ) = lb

= ( x + 3 ) ( 2x + 1 )

= x ( 2x + 1 ) + 3 ( 2x + 1 )

= 2x^2 + x + 6x + 3

= 2x^2 + 7x + 3

6 0

2 years ago