Answer:
Glaciers.
Explanation:
Glaciers are masses of ice that forms in mountainous areas.
Answer:
What is a noble gas electron configuration?
A noble gas electron configuration is a configuration that completes the Octet Rule of achieving 8 valence electrons.
Atoms always behave in ways to achieve stability and as you probably know, Noble Gases are the most stable. Their configuration, with a full valence electron shell (8 electrons, when you add both the S & P sublevels together, this is why it’s called the Octet), is therefore desirable. This means metals on the far left of the table will lose electrons to achieve this noble gas configuration and nonmetals on the right will gain electrons (generally speaking).
For example; take Argon. Its electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6, meaning it has 8 valence electrons. Then, take Chlorine. It has the electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5, meaning it has 7 valence electrons so it’s a very unhappy camper. It typically gains an electron to achieve the 8 valence electrons Argon has (even using the same configuration of 1s^2 2s^2 2p^6 3s^2 3p^6) because it’s Mega jealous of Argon’ s stability. Side note: this is why chlorine typically has a -1 charge!
In summary, an atom achieving a “Noble Gas configuration” is the same as saying an atom fulfilling the Octet Rule. Both mean that there are 8 valence electrons (electrons in shell furthest from nucleus). This is a stable form many atoms seek to achieve (of course, what’s a good rule in chemistry if there aren’t exceptions!).
Answer:
your answer would be
A.predict the genotypic and phenotypic probabilities of possible offspring
Answer:
a. Rate constant: 1.2118x10⁻⁴ yrs⁻¹
b. The age of the object is 20750 years
Explanation:
a. We can solve the rate constant in an isotope decay by using Half-Life, as follows:
K = Ln 2 / Half-life
K = ln 2 / 5720 years =
<h3>1.2118x10⁻⁴ yrs⁻¹</h3><h3 />
b. The general equation of isotope decay is:
Ln [A] = -kt + Ln [A]₀
<em>Where [A] is concentration of the isotope after time t, </em>
<em>k is rate constant</em>
<em>and [A]₀ initial concentration of the isotope.</em>
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Computing the values of the problem:
Ln [0.89x10⁻¹⁴] = -1.2118x10⁻⁴ yrs⁻¹t + Ln [1.1x10⁻¹³]
-2.5144 = -1.2118x10⁻⁴ yrs⁻¹t
20750 years = t
The age of the object is 20750 years
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