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2 years ago

14

What would be the difference in your weight (remember weight is the force of gravity acting on you) if you were 3 times further

from the center of the earth than you are now? What about 7 times?

1 answer:

AnnyKZ [126]2 years ago

7 0

Answer:

It would be 3 times as much gravity or 7 times

Explanation:

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Science fair ideas? please help

egoroff_w [7]

You can Maybe do a volcano?

8 0

3 years ago

Read 2 more answers

Compounds X and Y are both C6H13Cl compounds formed in the radical chlorination of 3-methylpentane. Both X and Y undergo base-pr

zubka84 [21]

Answer:

Y is a 3-chloro-3-methylpentane.

The structure is shown in the figure attached.

Explanation:

The radical chlorination of 3-methylpentane can lead to a tertiary substituted carbon (Y) and to a secondary one (X).

The E2 elimination mechanism, as shown in the figure, will happen with a simulyaneous attack from the base and elimination of the chlorine. This means that primary and secondary substracts undergo the E2 mechanism faster than tertiary substracts.

6 0

2 years ago

A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution

madam [21]

<u>Answer:</u> The initial pH of the HCl solution is 3

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL$

Putting values in above equation, we get:

$1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M$

1 mole of HCl produces 1 mole of $H^+$ ions and 1 mole of $Cl^-$ ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.001M$

Putting values in above equation, we get:

$pH=-\log (0.001)\\\\pH=3$

Hence, the initial pH of the HCl solution is 3

6 0

3 years ago

someone pls help me with my chemistry test plsss my teacher changes the questions so I can't search them up. its 21 questions so

shusha [124]

Answer:

Correct option is

B

5 liters of CH

4

(g)NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

7 0

2 years ago

A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif

slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

$Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})$

where,

Q = heat absorbed by metal = 186.75 J

$m_1$ = Mass of metal= 19 g

$T_1$ = Initial temperature of metal = $35^oC$

$T_2$ =Final temperature of metal = $175^oC$

$c$ = specific heat of metal= ?

$186.75 J=19 g\times c\times (175^oC-35^oC)$

$c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}$

$c=0.0702J/g^oC$

0.0702J/g°C the specific heat capacity of the metal.

6 0

3 years ago