which substance would not be used for preparing a pure crystalline magnesium sulfate by reaction with dilute hydrochloric acid

Given that the molar mass of NaCl is 58.44 g/mol, Solve for the molarity of a solution that contains 87.75 g of NaCl in 500 mL o

aliina [53]

Molarity is defined as the number of moles of solute per 1 L of solvent.

the mass of NaCl in the solution is 87.75 g

number of moles of NaCl is calculated by dividing mass present by molar mass

number of NaCl moles = 87.75 g / 58.44 g/mol = 1.502 mol

the number of NaCl moles in 500 mL is - 1.502 mol

therefore number of NaCl moles in 1000 mL is - 1.502 mol/ 500 mL x 1000 mL/L = 3.004 mol

molarity of NaCl is - 3.004 M

answer is D. 3.00 M

5 0

3 years ago

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For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at

maw [93]

Answer:

$2.55*10^{11$

Explanation:

Equation for the heterogeneous system is given as:

$2A_{(aq)} + 3 B_{(g)} + C_{(l)}$ ⇄ $2D_{(s)}$ $+$ $3E_{(g)}$

The concentrations and pressures at equilibrium are:

$[A] = 9.68*10^{-2}M$

$P_B = 9.54*10^3Pa$

$[C]=14.64M$

$[D]=10.11M$

$P_E=9.56*10^4torr$

If we convert both pressure into bar; we have:

$P_B = 9.54*10^3Pa$

$P_B = (9.54*10^3)*\frac{1}{10^5} bar$

$P_B=9.54*10^{-2}bar$

$P_E=9.56*10^4torr$

1 torr = 0.001333 bar

$9.54*10^4 *0.001333 = 127.5 bar$

$K=\frac{[P_E]^3}{[A]^2[P_B]^3}$

$K=\frac{(127.5)^3}{(9.68*10^{-2})^2(9.54*10^{-2})^3}$

$K=2.55*10^{11$

3 0

3 years ago

To maximize the yield in a certain manufacturing process, a solution of a weak monoprotic acid that has a concentration between

stira [4]

Answer: C 115 ml

Explanation:

If you have a solution of a monoprotic acid, it means that it has the form HA (just one Hydrigen atom). Therefore, one molecule of acid is going to react with just one molecule of NaOH.

So, if you have a solution of 100 ml of 0,2 HA acid, it is going to react with a 100 ml of 0,2 M NaOH solution. Beacause we know that the acid can be a little more concentrated than 0,2 M (0,2-0,3), it probably needs a little more than 100 ml of NaOH to react. So, the answer is C.

in 100 ml of 0,2M acid you can find 0,002 mol of HA

in 100 ml of 0,3 M acid you can find 0,003 mol of HA

in 100 ml of 0,2 M NaOH you can find 0,002 mol of NaOH

the answer can not be 200 because in 200 ml of 0,2 M NaOH there are 0,004 mol of NaOH, which is more than 0,003 mol.

0 0

4 years ago

The crust’s role in _______ allows it to provide the raw materials necessary for life on earth. a. the rock cycle b. biogeochemi

kow [346]

The answer is c follies fuel

6 0

3 years ago

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Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Zinaida [17]

Answer:

od

Explanation:

when burning a chemical compound the lighter element seperates from the stronger one

6 0

3 years ago