<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
Area of triangle = 1/2 bh
60 = 1/2 (15) h
8 = h
Quadrilateral area = h x (b1 + b2)/2 = 8 x (15+9)/2 = 96 sq units
96 -60 = triangle BAD area = 36 sq units
Answer:
? = 14
Step-by-step explanation:
let us say that ? = x
7^x * 7^5^4 = 7^34
When you have a power to a power you multiply
7^x * 7^20 = 7^34
when you multiply common bases you add the power. since all the bases aer the same just look at the power
7^34-20 = 7^x
7^14 = 7^x
Since the measure of angle 
is 
The measure of its reference angle = 
=
Now we have to compute the value of 
The value of (
) lies in the fourth quadrant. In fourth quadrant, the value of tan is always negative.
So, 
= -1.
32/1x5/6=160/6
6 goes into 160 26 times, with an extra 4.
Your answer is 26 4/6, or 26 2/3.
Hope this helps :-)
