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eimsori [14]
3 years ago
5

If a student was randomly guessing while completing a 20 question multiple choice exam, what is the probability they would score

a 50% or higher
Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

you want 4 correct and 16 incorrect

there are 20 questions

each question has four answers, so

P(right answer) = 1/4

P(wrong answer) = 3/4

----

Since you want 4 correct of 20 we have a combination of 20C4

This is a binomial problem where p = 1/4, q = 3/4 and we get

(20 "choose" 4)*(probability correct)^(number correct)*(probability incorrect)^(number incorrect)

putting numbers in we get

(20c4)*(1/4)^4*(3/4)^16

This gives us

~ .189685

Step-by-step explanation:

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The sum, because the product is for multiplication the quotient is for division and the difference is for subtraction. So that leaves the sum. It’s for addition.
4 0
3 years ago
FInd the GCF of the numbers using prime factorizations.
lesya [120]

Answer:

GCF(330, 75, 450, 225) = 15

Steps:

Prime factorization of the numbers:

330 = 2 × 3 × 5 × 11

75 = 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

225 = 3 × 3 × 5 × 5

GCF(330, 75, 450, 225)

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3 0
3 years ago
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nikklg [1K]
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7 0
3 years ago
F(x)=5x+6;g(x)=7x-2 qfjnd (f+g)(x)
Likurg_2 [28]

Answer:

12x+4

Step-by-step explanation:

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7 0
2 years ago
A number close to 1,772 that is easily divisible by 90
VashaNatasha [74]
<h2>1,800</h2>

- - - - - - - - - - - - - - - - - -

Let's try to divide 1,772 and see how much math we need to do...

1,772 / 90 = 19.6888888889

Well, clearly we need more than 1,772!

- - - - - - - - - - - - - - - - - -

Now, play around with adding numbers.

(I'm gonna skip all the experimenting, here's the closest # available for easy division!)

⇣

1,800 / 90 = 20

7 0
2 years ago
Read 2 more answers
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