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Sunny_sXe [5.5K]
3 years ago
12

Write an algebraic expression to model the unknown number problem.

Mathematics
2 answers:
Brrunno [24]3 years ago
6 0

Answer:

1,2,4

Step-by-step explanation:

Morgarella [4.7K]3 years ago
5 0

Answer:

A. You can replace ‘a number’ with a variable to represent an unknown value.

C. Product means the result of multiplying two numbers.

D. The coefficient is 15.

E. In algebraic notation, you can represent the product of a number and a variable by writing the number and variable next to each other.

Step-by-step explanation:

EDGE 2020

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A regular hexagon has an area of 750.8 cm. The side length is 17 cm. Find the apothem.
kompoz [17]

Since, a regular hexagon has an area of 750.8 square cm and The side length is 17 cm.

We have to find the apothem of the regular hexagon.

The formula for determining the apothem of regular hexagon is s \div {{2 \tan (\frac{180}{n})}, where 's' is any side length of regular hexagon and 'n' is the number of sides of regular hexagon.

So, apothem = 17 \div {2 tan(\frac{180}{6})

= 17 \div {2 tan(30)

= 17 \div {1.15}

= 14.78 units

Therefore, the measure of apothem of the regular hexagon is 14.7 units.

Option B is the correct answer.

5 0
3 years ago
I’m short word form 2,000,000+500,000+30,000+5,000+8
sasho [114]

Answer:

2,535,008

two million , five hundred thirty five thousand, eight

4 0
2 years ago
What is the answer I need help
netineya [11]

Answer:

i am very sorry i dont know the answer....

again very sorry...

Step-by-step explanation:

5 0
2 years ago
A solid cylinder has a radius of 4 cm and a length of 8 cm is melted down and recast in a solid cube find the dimension of the c
zhannawk [14.2K]

Answer:

7.37108cmx7.37108cmx7.37108cm

Step-by-step explanation:

Find the volume of the cylinder then take the cube route of that. You should end up with ~7.38108cm which is the length, width, and height of your cube. The volume is 402.12386cm cubed.

5 0
3 years ago
Read 2 more answers
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
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