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andre [41]
4 years ago
15

Length of the leg??

Mathematics
2 answers:
masya89 [10]4 years ago
8 0

Answer:

10

Step-by-step explanation:

mr_godi [17]4 years ago
8 0
Answer

10

Solution

a2=c2-b2
a2=26 2 - 24 2
a= square root of 100
a = 10
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A flea weighs 8 decigrams, and an ant weighs 3 milligrams. How much more does a flea weigh than an ant?
dusya [7]
In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
                     = 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
                                                                                   = 797 milligrams.
So the flea weighs 797 milligrams more than the ant.

5 0
4 years ago
Read 2 more answers
 A map of a highway has a scale of 2 inches=45 miles. The length of the highway on the map is 9 inches. There are 7 rest stops e
Sedaia [141]

Answer:

25.7 miles apart

Step-by-step explanation:

this may not be right, if its not im sory

6 0
3 years ago
Help me pls pls pls :(
sveta [45]
740 square meters

Just find the areas of all the faces of the prism. And add then all up:

Area of rectangular base (bottom):
16 • 10= 160 square meters

Area of triangle facing front:
1/2 • 15 • 16= 120
Multiply 120 by 2 cause theres a same triangle facing back the prism: 120 • 2= 240

Area of rectangle facing right:
10 • 17= 170
Multiply 170 by 2 cause theres a same rectangle facing left the prism: 170 • 2= 340

Add them all up together:
160+ 240+340= 740

Comm.ent me if u have any questions

MARK ME BRAINLIEST TYSM! Say if my answer was wrong/right!
3 0
3 years ago
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17. Complete the triangles so that the number in the centre is the sum of the numbers on the
Gre4nikov [31]

Answer:

i hop you will know the answer soon

Step-by-step explanation:

sorry i dont know

7 0
2 years ago
What is the following quotient 6-3(^3√6)/^3√9
azamat

Answer:

2\sqrt[3]{3}-\sqrt[3]{18}

Step-by-step explanation:

We first rationalize the denominator.  This means we multiply the numerator and denominator by a factor that will make the denominator a whole number.

Our denominator is \sqrt[3]{9}; this can also be written as 9^{\frac{1}{3}}.

For 9 to be a whole number, its exponent must be a whole number.  We want to add 2/3 to the exponent of 9 on the bottom; this means we multiply by 9^{\frac{2}{3}}:

On the numerator, this gives us:

6(9^(2/3))-3(6^(1/3))(9^(2/3))

= 6\sqrt[3]{9(9)} -3\sqrt[3]{2(3)}(\sqrt[3]{9(9)})  \\\\=6\sqrt[3]{3(3)(3)(3)}-3\sqrt[3]{2(3)(3)(3)(3)(3)}\\\\=6(3)\sqrt[3]{3}-3(3)\sqrt[3]{2(3)(3)}\\\\=18\sqrt[3]{3}-9\sqrt[3]{18}

On the denominator, we will have:

(9^(1/3))(9^(2/3)) = 9^(3/3) = 9^1 = 9

This gives us:

\frac{18\sqrt[3]{3}-9\sqrt[3]{18}}{9}\\\\=2\sqrt[3]{3}-\sqrt[3]{18}

6 0
3 years ago
Read 2 more answers
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