In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
= 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
= 797 milligrams.
So the flea weighs 797 milligrams more than the ant.
Answer:
25.7 miles apart
Step-by-step explanation:
this may not be right, if its not im sory
740 square meters
Just find the areas of all the faces of the prism. And add then all up:
Area of rectangular base (bottom):
16 • 10= 160 square meters
Area of triangle facing front:
1/2 • 15 • 16= 120
Multiply 120 by 2 cause theres a same triangle facing back the prism: 120 • 2= 240
Area of rectangle facing right:
10 • 17= 170
Multiply 170 by 2 cause theres a same rectangle facing left the prism: 170 • 2= 340
Add them all up together:
160+ 240+340= 740
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Answer:
i hop you will know the answer soon
Step-by-step explanation:
sorry i dont know
Answer:
![2\sqrt[3]{3}-\sqrt[3]{18}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B3%7D-%5Csqrt%5B3%5D%7B18%7D)
Step-by-step explanation:
We first rationalize the denominator. This means we multiply the numerator and denominator by a factor that will make the denominator a whole number.
Our denominator is ![\sqrt[3]{9}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D)
; this can also be written as 
.
For 9 to be a whole number, its exponent must be a whole number. We want to add 2/3 to the exponent of 9 on the bottom; this means we multiply by 
:
On the numerator, this gives us:
6(9^(2/3))-3(6^(1/3))(9^(2/3))
= ![6\sqrt[3]{9(9)} -3\sqrt[3]{2(3)}(\sqrt[3]{9(9)}) \\\\=6\sqrt[3]{3(3)(3)(3)}-3\sqrt[3]{2(3)(3)(3)(3)(3)}\\\\=6(3)\sqrt[3]{3}-3(3)\sqrt[3]{2(3)(3)}\\\\=18\sqrt[3]{3}-9\sqrt[3]{18}](https://tex.z-dn.net/?f=6%5Csqrt%5B3%5D%7B9%289%29%7D%20-3%5Csqrt%5B3%5D%7B2%283%29%7D%28%5Csqrt%5B3%5D%7B9%289%29%7D%29%20%20%5C%5C%5C%5C%3D6%5Csqrt%5B3%5D%7B3%283%29%283%29%283%29%7D-3%5Csqrt%5B3%5D%7B2%283%29%283%29%283%29%283%29%283%29%7D%5C%5C%5C%5C%3D6%283%29%5Csqrt%5B3%5D%7B3%7D-3%283%29%5Csqrt%5B3%5D%7B2%283%29%283%29%7D%5C%5C%5C%5C%3D18%5Csqrt%5B3%5D%7B3%7D-9%5Csqrt%5B3%5D%7B18%7D)
On the denominator, we will have:
(9^(1/3))(9^(2/3)) = 9^(3/3) = 9^1 = 9
This gives us:
![\frac{18\sqrt[3]{3}-9\sqrt[3]{18}}{9}\\\\=2\sqrt[3]{3}-\sqrt[3]{18}](https://tex.z-dn.net/?f=%5Cfrac%7B18%5Csqrt%5B3%5D%7B3%7D-9%5Csqrt%5B3%5D%7B18%7D%7D%7B9%7D%5C%5C%5C%5C%3D2%5Csqrt%5B3%5D%7B3%7D-%5Csqrt%5B3%5D%7B18%7D)
