Answer:
D) There are 6 grams of monosaccharides and 6 grams of disaccharides in the cookies.
Explanation:
A) There are more mono- and disaccharides than cellulose in the cookies. = True
The statement is true because, out of the 22 grams of total carbohydrates,there are 12 grams of sugars (mono- and disaccharides) and 2 grams of fiber in the chocolate mint cookies
B) There are 8 grams of carbohydrates in the cookies that are not monosaccharides, disaccharides, or fiber. = True
This statement is true because out of the 22 grams of total carbohydrates,there are 12 grams of sugars and 2 grams of fiber in the chocolate mint cookies. Therefore, the remaining 8 g of carbohydrates are neither sugars nor fibers.
C) The majority of the carbohydrates in the cookies will be able to be broken down via hydrolysis reactions when eaten. = True
This statement is true because out of the 22 g of carbohydrates in the cookies, only 2 g of cellulose fiber can not be broken down by the human body via hydrolysis. Other forms of carbohydrates are broken down by the body.
D) There are 6 grams of monosaccharides and 6 grams of disaccharides in the cookies. = False
This statement is false because the ratio of the monosaccharides to disaccharides in the sugar was not statedor whether the sugar present, is a monosaccharide or disaccharide.
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Answer:
False
Explanation:
Sound does not travel at all in space. The vacuum of outer space has essentially zero air. Because sound is just vibrating air, space has no air to vibrate and therefore no sound. ... Radio is a form of electromagnetic radiation just like light and can therefore travel through the vacuum of space just fine.
Answer:
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Explanation:
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Answer:
Option (c).
Explanation:
The hemoglobin is the important protein present in the red blood cells. The hemoglobin molecules helps in the transport of oxygen and carbon dioxide in the body.
The iron is important for the hemoglobin molecule formation. The deficiency in the iron can cause the abnormal hemoglobin structure. The mice hemoglobin can binds with the only 50% of the oxygen molecules as compared with the wild type mice.
Thus, the correct answer is option (c).