3 years ago

h(x) = x^2 + 2x - 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5

Mathematics

1 answer:

Vitek1552 [10]3 years ago

5 0

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3 years ago

h(x) = x^2 + 2x - 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5 ​

h(x) = x^2 + 2x - 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5