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3 years ago

h(x) = x^2 + 2x - 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5

Mathematics

1 answer:

Vitek1552 [10]3 years ago

5 0

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Does Anyone know this?

lukranit [14]

Answer:

∠AEC = 139°

Step-by-step explanation:

Since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1

∠AED = ∠AEB + ∠BEC + ∠CED = 180 ← straight angle

Substitute values into the equation

11x - 12 + 4x + 1 + 4x + 1 = 180, that is

19x - 10 = 180 ( add 10 to both sides )

19x = 190 ( divide both sides by 19 )

x = 10

Hence

∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11, hence

∠AEC = (15 × 10) - 11 = 150 - 11 = 139°

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3 years ago

HELP ME PLZZ I NEED HELP WITH THIS!!

Alina [70]

Answer:

4.50

Step-by-step explanation:

First add 50 and 40 to get 90. Then multiply that by 0.05 to get 4.5.

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3 years ago

What two rational expressions sum to <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%2B2%7D%7Bx%5E%7B2%7D-9%2B8%20%7D" id="TexFor

bulgar [2K]

Answer:

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

Step-by-step explanation:

Given

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

Required

Fill in the gaps

Going by the given parameters, we have that

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

$x^2 - 9x + 8$ , when factorized is $(x-1)(x-8)$

Hence; the expression becomes

$\frac{4x+2}{(x-1)(x-8)} = \frac{A}{(x-8)(x-1)} + \frac{B}{(x-1)(x-8)}$

Combine Fractions

$\frac{4x+2}{(x-1)(x-8)} = \frac{A + B}{(x-8)(x-1)}$

Simplify the denominators

$4x + 2 = A + B$

By direct comparison

$A = 4x$

$B = 2$

Hence, the complete expression is

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

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4 years ago

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a rectangular field is 0.45 kilometers long and 0.3 kilometers wide what is the area of the field in square meters?

bekas [8.4K]

Answer:135000

Step-by-step explanation:

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3 years ago

The sum of two numbers is x If one of the numbers is 12, what is the other?

neonofarm [45]

X-12 will give the other number

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3 years ago

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h(x) = x^2 + 2x - 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5 ​

h(x) = x^2 + 2x - 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5