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Montano1993 [528]
3 years ago
11

the sides of the rectangle are inreased by a scale factor of 4. The perimeter of the smaller retangle is 20 cm. What is the peri

meter of the larger rectangle?
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0
The height of the smaller rectangle, let us say is 5
5 x 4 = 20
(multiply height of rectangle to scale factor)
the length is 4
4 x 4 = 16
(multiply length of rectangle to scale factor)

to find larger factor, divide smaller with larger
16/20 = 1/4

scale factor should be 1/4

multiply 20 with 4

perimeter of larger should be 80

hope this helps

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Answer:

3x - 4 = -12

Step-by-step explanation:

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Find the circumference of a circle with a radius of 35 inches in terms of 7 and to the nearest tenth of an inch.​
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Answer and Step-by-step explanation:

The circumference formula for a circle is:

C = 2\pi r

Plug 35 in for r (radius) and solve.

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So, approximately 219.9 in^2 is the answer.

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2 years ago
The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

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Answer:

the answer is X<5/3 correct me if i'm wrong

Step-by-step explanation:

hope this helps

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