Answer:
ΔH = -135.05 kJ
Explanation:
(1) 2 ClF(g) + O₂(g) → Cl₂O(g) + OF₂(g) ΔHo = 167.5 kJ
(2) 2 F₂(g) + O₂(g) → 2 OF₂(g) ΔHo = −43.5 kJ
(3) 2 ClF₃(l) + 2 O₂(g) → Cl₂O(g) + 3 OF₂(g) ΔHo = 394.1 kJ
We can use Hess' Law to calculate the ΔH of reaction:
ClF(g) + 1/2O₂(g) → 1/2Cl₂O(g) + 1/2OF₂(g) ΔHo = 167.5 x 1/2 = 83.75 kJ
F₂(g) + 1/2O₂(g) → OF₂(g) ΔHo = −43.5 x 1/2 = -21.75 kJ
1/2Cl₂O(g) + 3/2 OF₂(g) → ClF₃(l) + O₂(g) ΔHo = 394.1 x -1 x 1/2 = -197.05kJ
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(4) ClF (g) + F₂ (g) → ClF₃ (l) ΔH = 83.75 kJ-21.75 kJ-197.05kJ
ΔH = -135.05 kJ/mol
Equal pressures from the ideal gas equation (P = nRT/V) ... same moles, T and V... P must be the same. <span>Lighter gas has greater RMS speed .... KE = 1/2mv² mass and speed inversely proportional </span>
<span>Same KE .... all gases at same T have same KE </span>
Microscale could be best bet as evaboration and other factors can come in play. otherwise contact angle measurements could have something related calculated via surface tension.
something that is possible, calculating mols via gravimetry.
finding the suitable material could be tricky as if it needs to be instant. silica gel doesn't necessarily work
adsorption vs. absorption
