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miss Akunina [59]
3 years ago
15

What is the relationship between the concentration of the hydronium and hydroxide ion and pH in any water solution?

Chemistry
1 answer:
frez [133]3 years ago
4 0

Answer:

The <u>concentration of hydronium ions</u> and the pH value is related by the equation: <u> pH=-Log[H+]</u>

Explanation:

We have two different concepts pH and concentration of <u>hydronium ions</u>. Lets start with the hydronium ion.

An hydronium ion is a species that is produced by an <u>acid</u>:

HA~->~H^+~+~A^-

Aditionally, we can have the production of <u>hydroxide ions</u>. The subtances that have the capacity to produce this ions are called <u>"bases"</u>:

BOH~->~B^+~+~OH^-

Now we can continue "pH"

The <u>pH is a scale</u> that indicates if the substance is and <u>acid</u> (higher concentration of H^+), <u>neutral</u> (equal amounts of H+ and OH^-) or <u>basic</u> (higher amount of OH^-).

Finally, the "pH" is calculated with the concentration of the hydronium ions (

H^+), the letter <u>"p" is "-Log"</u>, therefore:

pH=-Log[H^+]&#10;

I hope it helps!

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From: www.middleschoolchemistry.com

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The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

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Let's find the number of periods elapsed (x), let us see:

T = x*P

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25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

m \approx \dfrac{53.3}{6.021}

\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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