Answer:
5.3%
Explanation:
Let the volume be 1 L
volume , V = 1 L
use:
number of mol,
n = Molarity * Volume
= 0.8846*1
= 0.8846 mol
Molar mass of CH3COOH,
MM = 2*MM(C) + 4*MM(H) + 2*MM(O)
= 2*12.01 + 4*1.008 + 2*16.0
= 60.052 g/mol
use:
mass of CH3COOH,
m = number of mol * molar mass
= 0.8846 mol * 60.05 g/mol
= 53.12 g
volume of solution = 1 L = 1000 mL
density of solution = 1.00 g/mL
Use:
mass of solution = density * volume
= 1.00 g/mL * 1000 mL
= 1000 g
Now use:
mass % of acetic acid = mass of acetic acid * 100 / mass of solution
= 53.12 * 100 / 1000
= 5.312 %
≅ 5.3%
Answer:
the blanket of gases that surrounds Earth and some other planets
Explanation:
The best definition of the atmosphere is that it is a portion of the earth that is a made up of a blanket of gases.
- The atmosphere is not peculiar to the earth alone, some other planets also have atmospheric cover.
- The earth's atmosphere is divided into many different layers.
- The weather we see and experience on the earth surface is conditioned within the troposphere.
- This troposphere is the closest layer to the surface.
Answer:
146 g
Explanation:
Step 1. Calculate the <em>molar mass</em> of NaNO₃
Na = 22.99
N = 14.01
3O = 3 × 16.00 = 48.00
Total = 85.00 g/mol
Step 2. Calculate the <em>mass</em> of NaNO₃
Mass of NaNO₃ = 1.72 × 85.00/1
Mass of NaNO₃ = 146 g
Answer:
17.3124 grams
Explanation:
Given;
Amount of heat to be produced = 175 kJ
Molar mass of the carbon monoxide = 12 + 16 = 28 grams
Now,
The standard molar enthalpy of carbon monoxide = 283 kJ/mol
Thus,
To produce 175 kJ heat, number of moles of CO required will be
= Amount heat to be produced / standard molar enthalpy of CO
or
= 175 / 283
= 0.6183
Also,
number of moles = Mass / Molar mass
therefore,
0.6183 = Mass / 28
or
Mass of the CO required = 0.6183 × 28 = 17.3124 grams
Answer:
oxygen
Explanation:
I am pretty sure it is that but you should still check
