For this case we have the following vector:
u = (1, -3)
When multiplying by the scalar 1/3 we have:
1 / 3u = (1/3) (1, -3)
Rewriting the new vector we have:
1 / 3u = (1/3, -3/3)
1 / 3u = (1/3, -1)
Answer:
1 / 3u = (1/3, -1)
Answer:
The average rate of change is 8
Step-by-step explanation:
Mathematically, we have the average rate of change over a given interval as;
f(b) - f(a)/b-a
Where the interval is [a,b]
With respect to this question, a = 3 and b = 5
f(a) = f(3) = 3^2 - 4 = 9-4 = 5
f(b) = f(5) = 5^2 - 4 = 25-4 = 21
Thus, the average rate of change over the intervals will be;
(21-5)/(5-3) = 16/2 = 8
16 represents the # of small pair of gloves and 2 is the # of large pair of gloves
Answer:
![x=-5,\\y=\frac{13}{2}](https://tex.z-dn.net/?f=x%3D-5%2C%5C%5Cy%3D%5Cfrac%7B13%7D%7B2%7D)
Step-by-step explanation:
![\begin{cases}x+2y=8,\\x=-5\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dx%2B2y%3D8%2C%5C%5Cx%3D-5%5Cend%7Bcases%7D)
Substitute the second equation into the first (
):
![-5+2y=8,\\2y=13,\\y=\boxed{\frac{13}{2}}](https://tex.z-dn.net/?f=-5%2B2y%3D8%2C%5C%5C2y%3D13%2C%5C%5Cy%3D%5Cboxed%7B%5Cfrac%7B13%7D%7B2%7D%7D)
The second equation already denotes
. Therefore,
![\boxed{x=-5,\\y=\frac{13}{2}}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D-5%2C%5C%5Cy%3D%5Cfrac%7B13%7D%7B2%7D%7D)