Answer:
Cindy made 3 decorations with the ribbons
Step-by-step explanation:
Since Cindy used 1/10 of a metre of ribbon to make just one decoration that she obtained by dividing 3/10 of a meter of ribbon into equal parts, then we can calculate the number of decorations that Cindy made. In this scenario, all we need is an idea on how to divide fractions and we are good to go.
If Cindy used 1/10 of a metre obtained by dividing 3/10 of a metre of ribbon to make decorations, then the number of decorations she made can be gotten by dividing 3/10 by 1/10
i.e 3/10 ÷ 1/10
= 3/10 × 10/1
= 3 decorations.
That is she used 1/10 + 1/10 + 1/10 = 3/10 to make (3 decorations).
Answer:
none of them
Step-by-step explanation:
Answer:
D. 11.8 cm
Step-by-step explanation:
This triangle is a 30°-60°-90° triangle. There is a shortcut to find the lengths of the sides of a 30°-60°-90° triangle. The longest side is the hypotenuse. The longest side is double the shortest side or, the shortest side is half the longest side. Here the longest side is 5, so the short leg (shortest side) is 2.5
The other shortcut is that the longer leg is the
short leg×sqroot3
Here, the short leg is 2.5, so the long leg is 2.5×sqroot3
Perimeter is all the sides added together.
5 + 2.5+ 2.5×sqrt3
Do the times first.
5 + 2.5 + 4.3
= 11.8
Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
Answer:
He has saved $140.
Step-by-step explanation:
Since 35% translates to 0.35, 35% of 400 is (0.35)(400) = 140
