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blsea [12.9K]
3 years ago
12

I need help please i need a answer

Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0

Answer:

5

Step-by-step explanation:

Given

28.95 + 34.05b ≤ 200 ( subtract 28.95 from both sides )

34.05b ≤ 171.05 ( divide both sides by 34.05 )

b ≤ 5.02349..

Thus 5 black inks were purchased

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Please help me..make it right..
mr_godi [17]

Answer: 8/9

Step-by-step explanation:

The common multiple they all share is 18, so change the denominator to that for all the fractions.

2/3 = 12/18

13/18 = 13/18

7/9 = 14/18

5/6 = 15/18

The next answer would be 16/18 which is equivalent to 8/9

4 0
3 years ago
Read 2 more answers
Find the height of a square pyramid that has a volume of 32 cubic feet and a base length of 4 feet. . . . a. 2 feet. b. 4 feet.
Mademuasel [1]
Volume of Pyramid = (1/3)*(base area) * height.

32 ft³  =  (1/3)*(4*4)* h.        Since Pyramid is square based.

32 = (16/3)*h

16h/3 = 32

h = 32*3/16

h = 6

Height = 6 feet.  Option C. 

4 0
3 years ago
Zadanie optymalizacyjne z matematyki. Proszę o rozwiązanie i wyjaśnienie
Yakvenalex [24]

Volume of the pyramid:

V=\dfrac{s^2h}3

Perimeter of the cross-section:

40=\sqrt2\,s+2\sqrt{\dfrac{s^2}2+h^2}=\sqrt2\left(s+\sqrt{s^2+2h^2}\right)

\implies h=\sqrt{\dfrac{(20\sqrt2-s)^2-s^2}2}=\sqrt{400-20\sqrt2\,s}

Area of the cross-section:

P=\dfrac12(\sqrt2\,s)h=\dfrac{sh}{\sqrt2}

\implies P=\dfrac{s\sqrt{400-20\sqrt2\,s}}{\sqrt2}=s\sqrt{200-10\sqrt2\,s}

First derivative test:

\dfrac{\mathrm dP}{\mathrm ds}=\dfrac{20\sqrt2-3s}{\sqrt{4-\dfrac{\sqrt2}5s}}=0\implies s=\dfrac{20\sqrt2}3

Then the height of the cross-section/pyramid is

h=\sqrt{400-20\sqrt2\,s}=\dfrac{20}{\sqrt3}

The volume of the pyramid that maximizes the cross-sectional area P is

V=\dfrac{\left(\frac{20\sqrt2}3\right)^2\frac{20}{\sqrt3}}3=\dfrac{16000}{27\sqrt3}

5 0
3 years ago
What is the next number in the sequence?<br> 1, 4, 13, 40, 121,...
Nataliya [291]
The pattern here is the number times 3 then plus 1

We can check this by plugging it in.

1×3=3
3+1=4
4 is the next number in our sequence so the pattern works.

We can continue to check this with the rest of our sequence.

4×3=12
12+1=13
13 is the next number in our sequence so the pattern works.

13×3=39
39+1=40
40 is the next number in our sequence so the pattern works.

40×3=120
120+1=121
121 is the next number in our sequence so the pattern works.


We can find the next numbed in the sequence by continuing the patter
121×3=363
363+1=364

So the next number in the sequence is 364
8 0
3 years ago
PLEASE HELP!
Zielflug [23.3K]

Answer:

C and D

Step-by-step explanation:

Want explanation? Comment

5 0
3 years ago
Read 2 more answers
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