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3 years ago

3. Who set up their equation correctly for the following question?

Mathematics

1 answer:

melisa1 [442]3 years ago

5 0

Heyy 3747484884 hwibdhdjens

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What is the product?<br><br> (-2x-9y2)(-4x-3)

Inessa [10]

Answer:

8x^2+6x+36xy^2+27y^2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the next term in the following sequence 8, 13, 6, -16, -49, -82

DochEvi [55]

Answer:

Unidentifiable.

Step-by-step explanation:

8 to 13 is +5. 13 to 6 is -7. 6 to -16 is -20. -20 to -49 is -19. -49 to -82 is -33.

There is no distinguishable pattern since the differences between the terms vary significantly and in unpredictable ways. Make sure to double check you've got all your numbers correctly. <3

3 0

3 years ago

Mario eats twice as many as Yolanda. If Yolanda eats 6 walnuts every day, how many walnuts does Mario eat in a week?

stepladder [879]

let

x-------> walnuts that Mario eats in a week

y-------> walnuts that Yolanda eats in a week

we know that

x=2y-------> equation 1

y=6*7-------> y=42 walnuts

substitute the value of y in equation 1

x=2*42-----> x=84 walnuts

therefore

the answer is

Mario eat in a week 84 walnuts

8 0

4 years ago

Veronica takes 1/3 of an hour to write 1/4 of a page of calligraphy.

Andreyy89

B because it takes 1 hour to complete 3/4 of a page so 3/3 = 1 hour 1 1/3 =1 and a third of an hour

8 0

3 years ago

Read 2 more answers

I don’t understand, HELPPP

goldenfox [79]

$\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4}$

First cross out the -6 and -36. Six will go into 6 one time and 6 will go into -36 six times so we have the following after crossing out.

$\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4}$
$\frac{xy^{3}z^5}{6x^{2}y^{2}z^4}$ <---After crossing out

Next cross out the x / x^2 which will give us the following:
$\frac{xy^{3}z^5}{6x^{2}y^{2}z^4}$
$\frac{y^{3}z^5}{6xy^{2}z^4}$ <---After crossing out

Now cross out the y^2 / y^3
$\frac{y^{3}z^5}{6xy^{2}z^4}$
$\frac{yz^5}{6xz^4}$ <----After crossing out

All that is left is to cross out the z^5 / z^4 and we are done.
$\frac{yz^5}{6xz^4}$
$\frac{yz}{6x}$ <----After crossing out and we are done.

$\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4} = \frac{yz}{6x}$

8 0

3 years ago