1 yard = 1760 yard x 5 = 8,800 which is b
ookies. OK
How to calculate 12 divided by 4
Long Division
Here we will show you step-by-step with detailed explanation how to calculate 12 divided by 4 using long division.
Before you continue, note that in the problem 12 divided by 4, the numbers are defined as follows:
12 = dividend
4 = divisor
Step 1:
Start by setting it up with the divisor 4 on the left side and the dividend 12 on the right side like this:
4 ⟌ 1 2
Step 2:
The divisor (4) goes into the first digit of the dividend (1), 0 time(s). Therefore, put 0 on top:
0
4 ⟌ 1 2
Step 3:
Multiply the divisor by the result in the previous step (4 x 0 = 0) and write that answer below the dividend.
0
4 ⟌ 1 2
0
Step 4:
Subtract the result in the previous step from the first digit of the dividend (1 - 0 = 1) and write the answer below.
0
4 ⟌ 1 2
- 0
1
Step 5:
Move down the 2nd digit of the dividend (2) like this:
0
4 ⟌ 1 2
- 0
1 2
Step 6:
The divisor (4) goes into the bottom number (12), 3 time(s). Therefore, put 3 on top:
0 3
4 ⟌ 1 2
- 0
1 2
Step 7:
Multiply the divisor by the result in the previous step (4 x 3 = 12) and write that answer at the bottom:
0 3
4 ⟌ 1 2
- 0
1 2
1 2
Step 8:
Subtract the result in the previous step from the number written above it. (12 - 12 = 0) and write the answer at the bottom.
0 3
4 ⟌ 1 2
- 0
1 2
- 1 2
Answer:
option 2
Step-by-step explanation:
2 / (3x - 1) ÷ 6 / (6x - 1)
= 2 / (3x - 1) * (6x - 1) / 6
= 1 / (3x - 1) * (6x - 1) / 3
= 6x - 1 / 9x - 3
Answer:
9
Step-by-step explanation:
Highest number is 19 lowest is 10. 19-10 is 9.
Answer:
84%
Step-by-step explanation:
We have to remember that z-scores are values to find probabilities for any <em>normal distribution</em> using the <em>standard normal distribution</em>, a conversion of the normal distribution to find probabilities related to that distribution. One way to find the above z-scores is:

As a result, we can say that one standard deviation above the mean is equal to a z-score = 1, or that one standard deviation below the mean is equal to a z-score = -1, to take some examples.
The corresponding cumulative probability for a z-score = 1 (<em>one standard deviation above the mean</em>) can be obtained from the <em>cumulative standard normal table</em>, that is, the cumulative probabilities from z= -4 (four standard deviations below the mean) to the value corresponding to this z-score = 1.
Thus, for a z-score = 1, the <em>cumulative standard normal table</em> gives us a value of P(x<z=1) = 0.84134 or 84.134. In other words, below z = 1, there are 84.134% of cases below this value.
Applying this for the case in the question, the percentage of test scores below 69 (one standard deviation above the mean) is, thus, 84.134%, and rounding to the nearest whole number is simply 84%.