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3 years ago

(40 points to best answer) (help ASAP)

Mathematics

1 answer:

aleksandrvk [35]3 years ago

5 0

Answer:

x=3.5

Step-by-step explanation:

We can use proportions to solve this problem. Put the side of one triangle over the same side of the other triangle.

6 4.2

------ = ----------

5 x

Using cross products

6x = 5*4.2

6x =21

Divide by 6

6x/6 = 21/6

x=3.5

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Kimberly makes 127.81 ounces and pours 15 cups how much goes in each cups

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Answer:

8.52

Step-by-step explanation:

127.81/15=

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4 years ago

One half Of a certain even integer plus One fifth Of The next consecutive even interger equals 48. Find The two intergers.

yaroslaw [1]

The integers are 68 and 70.

One half of 68 is 34.
One fifth of 70 is 14.
34 + 14 = 48 and 68 and 70 are consecutive even integers.

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3 years ago

WILL GIVE BRAINLIEST!

Nataly [62]

Answer:

The equation the circle is given by

${\bf 4x}^{\bf 2}+{\bf 4y}^{\bf 2}-{\bf 8x+0y-60}={\bf 0}$

Step-by-step explanation:

The general form of the circle is

$x^2+y^2+Dx+Ey+F=0\hfill (1)$

Given points are (5,0) , (0,4) and (2,4)

Let the points (5,0) , (0,4) and (2,4) be (x_1,y_1) , (x_2,y_2) and (x_3,y_3) respectively

The equation of the circle passes through given points (5,0) , (0,4) and (2,4)

Substituting the point (5,0) in (1)

$(-5)^2+(0)^2+D(5)+E(0)+F=0$

$25-5D+F=0$

$5D-F=25\hfill (2)$

Substituting the point (0,4) in

$(0)^2+(4)^2+D(0)+E(4)+F=0$

$16+4E+F=0$

$4E+F=-16\hfill (3)$

Substituting the point (2,4) in

$(2)^2+(4)^2+D(2)+E(4)+F=0$

$4+16+2D+4E+F=0$

$2D+4E+F=-20\hfill (4)$

By solving the equations (2) ,(3) and(4) we get the values of D,E and F as below

$D=-2$ , $E=0$ and $F=-15$

substituting the values of D,E and F in (1) we get

$x^2+y^2-2x+(0)y-15=0$

Now multiplying the above equation into 4 we get

$4x^2+4y^2-8x+(0)y-60=0$

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3 years ago

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Pavlova-9 [17]

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