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Lesechka [4]
2 years ago
5

Alberto has a scale drawing of an object whose area is 12 square centimeters. The scale factor is 1:3 Alberto says that the area

of a real object is 36 square centimeters is Alberto's answer is correct.
WIL GIVE GIVE BRAINLIEST LOTS OF POINTS​
Mathematics
1 answer:
Shtirlitz [24]2 years ago
8 0

Answer:

No, Albert's answer is not correct

Step-by-step explanation:

For illustrative purposes, let's say the object is a rectangle with width 2cm and length 6cm.  

Therefore, area = width x length = 2 x 6 = 12 cm²

If the scale factor is 1 : 3, then each side of the real object should be 3 times larger than the scale drawing.

So the width = 2 x 3 = 6 cm

and the length = 6 x 3 = 18 cm

Therefore, the area of this rectangle would be 6 x 18 = 108 cm²

So the scale factor of the area is:  12 : 108 = 1 : 9

so Alberto's answer is incorrect, as 12 : 36 is NOT 1 : 9

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What is the slope of a line
Nina [5.8K]

Answer:

y=mx+b ( or do you mean the meaning)

Step-by-step explanation:

hope this helpssssss ?

3 0
3 years ago
Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How m
8_murik_8 [283]

Value of the given statement:

  1. 4.36
  2. 5
  3. 6
  4. 38
<h3>What is Probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

According to the given information:

1) There are a total of 10 slips after adding.

8 slip with 3 on it

2 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 11)  x 3 + (2/ 11)  x 9

24 / 11 + 24 / 11 = 4.36

2 )No of total slips after addition = 12

8 slip with 3 on it

4 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 12)  x 3 + (4 / 12)  x 9

2 + 3 = 5

3 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 6

24 + 18 + 9n / 10 + n  = 6

42 + 9n = 60 + 6n

3 n = 18

n = 6

4 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

expectation value = probability of 3 x 3 + probability of 9 x 9

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 8

24 + 18 + 9n / 10 + n  = 8

42 + 9n = 80 + 8n

n = 38

Minimum of 38 has to be added .

To know more about Probability visit:

brainly.com/question/17487084

#SPJ4

I understand that the question you are looking for is:

1:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add one additional $9$ to the bag? 2:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add two additional $9$'s (instead of just one) to the bag? 3:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do we have to add to make the expected value equal to $6$? 4:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do I have to add before the expected value is at least $8$?

4 0
2 years ago
What is the product?
Tanzania [10]

Answer:

=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

Step-by-step explanation:

\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}

Multiply the row of the first matrix to the column of the second matrix

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\

=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}

simplifying them we get

=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

8 0
3 years ago
11) Endpoint: (0,4), midpoint (-10, -3)<br> Find the endpoint?
earnstyle [38]

Answer:

(-20,-10)

Step-by-step explanation:

( - 10 \:  \:  - 3) = ( \frac{0 + x}{2}  \:  \:  \frac{4 + y}{2} )

Solve for.x coordinate

- 10 =  \frac{0 + x}{2}  \\  - 20 = 0 + x \\ x =  - 20

solve for y coordinate

- 3 =  \frac{4 + y}{2}  \\  - 6 = 4 + y \\  - 10 = y

5 0
4 years ago
Need help not quiz need help please and​
Eva8 [605]

Answer:

b

Step-by-step explanation:

..................................

6 0
3 years ago
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