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2 years ago

You have 5 cups of birdseed . You use 3/5 cup each day. How many days will your birdseed last

Mathematics

2 answers:

Alenkasestr [34]2 years ago

5 0

7 Days 25/5 cups of bird seed to start with and subtract 3/5 from it until you run out of bird seed

Marrrta [24]2 years ago

4 0

5 cups is equal to 25/5 cups. if we divide 25/5 by 3/5 which we should multiply by 5/3, the answer is 25/3 which you can say 8 and 1/3 days.
you can round up to 9 days

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lubasha [3.4K]

Answer:

Step-by-step explanation:

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2 years ago

What is the answer to <br> 6x> -54

Anestetic [448]

Answer:

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2 years ago

A General Motors buyer-incentive program offered a 5.5% rebate on the selling price of a new car. What rebate (in dollars) would

Mashcka [7]

Answer: he would receive a rebate of $1677.5

Step-by-step explanation:

A General Motors buyer-incentive program offered a 5.5% rebate on the selling price of a new car. This means that if the selling price of the new car is $x, the rebate (in dollars) that a customer would receive is

5.5/100 × x = 0.055 × x = 0.055x

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3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$