Problem 1:
1) 3/5x-1 x 3/4=9/10
3x/5-1 x 3/4=9/10
2) 3x/5-1 x 3/4=9/10
3x/5-3/4=9/10
3) 3x/5-3/4=9/10
+3/4 +3/4
4) 3x/5=33/20
5) 5 x 3x/5= 5 x (33/20)
6) 3x=33/4
7) 3x=33/4
/3 /3
8) x=11/4
Problem 2:
1) 6/7+2/5x=-4/5
6/7+2x/5=-4/5
2) 6/7+2x/5=-4/5
-6/7 -6/7
3) 2x/5= --58/35
4) 5 x 2x/5= 5 x (--58/35)
5) 2x= --58/7
6) 2x= --58/7
/2 /2
x= --29/7
So first thing you need to understand is that ABC and AFE are congruent triangles. This means we can find the other angles, based on ABC:
Angle FAE = 26.56505118 degrees
Angle AEF = 63.43494882 degrees
Angles ECD and DEC are both 45 degrees
Now, we can find the angles in ACE:
AEC = 71.56505118 degrees
ECA = 71.56505118 degrees
CAE = 36.86989764 degrees
Answer:
so you have $12.95. then you multiply it by 8% which gives you $13.986. Then you take 10% off of it, which gives you $12.5874.
<span>This problem is solved using the chain rule.
the area of the square is f(t) and the length of the side is g(t)
f(t)=g(t)^2
g'(t)=5
Using the chain rule
f'(t)=2*g(t)*g'(t)
The value of g(t) is sqrt(49) which is 7.
g'(t) is given as 5 cm/s
f'(t)=2*7*5=14*5=70cm^2/s</span>
