We are looking for the inner perimeter of the track. Since there are two semicircles, these mix to form one full circle so we can use the formula to find the circumference of the circle with a diameter of 60 m, which was given to us. With a diameter of 60m, the radius will be 30m. Now we can solve this problem.
C = 2πr
C = 2π(30)
C = 60π
The semicircle ends of the track are a distance of 60π m, and now we just need to add the lengths of the inner track which are 100 m each. So:
P = 60π + 100m + 100m
P = 200 + 60π
P = 388.5 m
Answer:
Follows are the solution is this query:
Step-by-step explanation:
In point a:
The explicatory variable mostly on X-axis is obtained only at the two-dimensional level or the Y-axis dependent variables, instead of catching the information, they also get diffusion plotted in the attached file please find it.
In point b:
Draw on the scatter diagram as just below the minimum-square correlation axis, which is defined in the attached file please find it.
In point c:
From the plot above, a positive relationship among even in the analysis of bone density, the dominant and non-dominant Arm. They can forecast its bone using bone density throughout the non-dominant arm and the Dominant arm power. They can conclude from the slopes of its regression model, which is inside a non-dominant arm, each unit raises bone strength by 0.936 throughout the dominant atm.
Hello,
y=35*6^x
==>ln(y)=ln(35)+x*ln(6)
==>e^ln(y)=e^(ln(35)+x*ln(6))
==>y=35*ln(6)*e^x≈62.711*e^x
Answer:
Zero
Step-by-step explanation:
The distance AB is ...
... √((5-1)²+(5-2)²) = √(16+9) = 5
The largest right triangle that can be constructed with AB as the hypotenuse is one with an altitude of 5/2 = 2.5 units. Its area will be ...
... (1/2)·5·2.5 = 6.25 . . . . square units
It is not possible to construct the triangle ABC described.
_____
In order to achieve the given area, ∠C would need to be 87.75° or smaller. It could not be 90°.
Answer:
The solution set can be given as:

Step-by-step explanation:
Given function:

To find the domain of the function in set notation.
Solution:
For the function
to exist the denominator must be ≠ 0
We have the denominator
which cannot be = 0.
Thus, we can find the domain of the function using the above relation.
The function
will not exist when:

Solving for 
Subtracting both sides by 6.


Dividing both sides by 2.

∴ 
Thus, the function will not exist at
. This means it has all real number solutions except -3.
The solution set can be given as:
