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Brut [27]
3 years ago
12

Solve for x in the equation x^2+2x+1=17

Mathematics
2 answers:
Leto [7]3 years ago
5 0
First, subtract 17 on both sides: x²+2x-16=0
this cannot be factored, so use the quadratic formula to solve for x:
b²-4ac=2²-4(10(-16)=4+64=68
√68=2√17
so x=(-2+2√17)/2 or x=(-2-2√17)/2
x=-1+√17 or x=-1-√17
Whitepunk [10]3 years ago
5 0

Answer:

 x=-1+\sqrt{17}   and   x=-1-\sqrt{17}

Step-by-step explanation:

x^2+2x+1=17

To solve for x , we set the right hand side =0

x^2+2x+1=17

Subtract 17 on both sides

x^2+2x-16=0

Now apply quadratic formula

x=\frac{-b+-\sqrt{b^2-4ac}}{2a}

From the given f(x), the value of a=1, b=2, c=-16

Plug in all the values in the formula

x=\frac{-2+-\sqrt{2^2-4(1)(-16)}}{2(1)}

 x=\frac{-2+-\sqrt{68}}{2}

 x=\frac{-2+-2\sqrt{17}}{2}

 x=-1+-\sqrt{17}

 x=-1+\sqrt{17}   and   x=-1-\sqrt{17}

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