Sean reads 60 minutes on wednesday
<em><u>Solution:</u></em>
Given that,
Let "x" be the number of minutes read on monday
Let "y" be the number of minutes read on tuesday
Let "z" be the number of minutes read on wednesday
<em><u>He reads 3 times as many minutes on Tuesday as he does on Monday</u></em>
Number of minutes read on tuesday = 3 times the number of minutes read on monday
y = 3x --------- eqn 1
<em><u>He reads 4 times as many minutes on Wednesday as he does on Monday</u></em>
Number of minutes read on wednesday = 4 times the number of minutes read on monday
z = 4x ------- eqn 2
<em><u>Sean reads 45 minutes on Tuesday</u></em>
y = 45
<em><u>Substitute y = 45 in eqn 1</u></em>
45 = 3x
x = 15
<em><u>Substitute x = 15 in eqn 2</u></em>
z = 4(15)
z = 60
Thus he reads 60 minutes on wednesday