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vova2212 [387]
3 years ago
15

PLEASE HELP ME!!!!! i really need it !!!

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0
F(x) =√x : Right


f(x) = x² : Wrong


Domain: x> or = to Zero & for x<0  then x∈ C


f(x) > or = to zero. Yes Real


The domain is all real & positive numbers
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58% of 250 pls quick I’m in a test rn Yr 7
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Answer:145

Step-by-step explanation:the answer is 145

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Which statement describes the definition of a function?
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Answer:

an activity or purpose natural to or intended for a person or thing.

Step-by-step explanation:

: >

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The table shows the price for shoe rental, games, and snacks at the bowling alley
monitta
First, find the total price she would have had to pay (without tax):
2.75+ 3(2.5)+ 1.75=12
If she has half-price multiply the total price by 0.5:
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6 0
3 years ago
Captain has $30 flame has a $20 note $5 notes . how much more moneny does captain have
SCORPION-xisa [38]

Captain has $30 money

Flame has $20 +$5 =$25

difference =30-25=5

Captain has $5 more money

5 0
2 years ago
someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your
Lunna [17]

Answer:

Part A) The area of the figure is 24\ units^{2}

Part B) The perimeter of the figure is 20\ units

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

A=\frac{1}{2}bh

<u>Area of triangle ABD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(9-5)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

<u>Area of triangle BCD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(5-1)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of the figure is

12\ units^{2}+12\ units^{2}=24\ units^{2}

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+AD

we have

A(-5,1),B(-8,5),C(-5,9),D(-2,5)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units

Find the distance BC

d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units

Find the distance CD

d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units

Find the distance AD

d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units

substitute the values

P=5+5+5+5=20\ units

7 0
3 years ago
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