![-17^0=(-17)^0=1](https://tex.z-dn.net/?f=-17%5E0%3D%28-17%29%5E0%3D1)
![\begin{gathered} (-2)^2\times(-2)^{-5}=(-2)^{2-5} \\ =(-2)^{-3} \\ =\frac{1}{(-2)^3} \\ =\frac{1}{-8} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28-2%29%5E2%5Ctimes%28-2%29%5E%7B-5%7D%3D%28-2%29%5E%7B2-5%7D%20%5C%5C%20%3D%28-2%29%5E%7B-3%7D%20%5C%5C%20%3D%5Cfrac%7B1%7D%7B%28-2%29%5E3%7D%20%5C%5C%20%3D%5Cfrac%7B1%7D%7B-8%7D%20%5Cend%7Bgathered%7D)
Thus, the final answers are 1 and -1/8.
Answer: She can buy a few.
Step-by-step explanation:
I can not anwer this uestion due to plagiarism
Answer:
Option (3)
Step-by-step explanation:
From the figure attached,
Area of the shaded region = Area of circle - (Area of the ΔOAB + Area of ΔOED)
Area of the circle = πr²
= π(5)²
= 25π cm²
Area of ΔOAB = 2(Area of ΔOCB)
AB = 6 cm
OC = 5 - 1 = 4 cm
By applying Pythagoras theorem in ΔOCB,
OB² = OC² + BC²
5² = 4² + BC²
BC² = 25 - 16
BC = √9 = 3 cm
Area of ΔOCB = ![\frac{1}{2}(OC)(BC)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28OC%29%28BC%29)
= ![\frac{1}{2}(4)(3)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%284%29%283%29)
= 6 cm²
Area of ΔAOB = 2(6) = 12 cm²
Area of ΔAOB = Area of ΔDOE = 12 cm²
Area of shaded region = 25π - (12 + 12)
= (25π - 24) cm²
Therefore, Option (3) will be the answer.