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artcher [175]
3 years ago
10

Please help me with this I need it now :)

Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer:

reverse it x-15=4 do 15+4=x

Step-by-step explanation:

You might be interested in
steve reads 20 pages of his graphic novel per hour . if the book has 200 pages and he reads for d hours , which expression shows
PolarNik [594]
The answer would be D. 200 - 20d.

This is because the question asks for pages left after reading for "d" (however many) hours. Since the book has 200 books, you'd subtract from that number since it's the "starting number" of pages. If he reads 20 pages per hour, you would multiply those together to get how many he has read, then subtract that number from 200, to get the amount of pages left.

I hope this helps!
7 0
3 years ago
PLEASE HELP MEEEEEEEEE
wariber [46]

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLEASE HELP W/ THIS QUESTION I ALLWAYS GET STUCK ON READING TIME!!!
Ad libitum [116K]

Answer:

2:40

Step-by-step explanation:

Short hand (hours): a little past 2

Long hand (minutes): 40 -- 8*5=40

6 0
2 years ago
Find the missing angle<br> m∠R=
Oxana [17]

Answer:

R = 90

Step-by-step explanation:

Triangles will always equal 180 degrees. If you add 61 + 29 = 90. If two of the three angles already equal 90 degrees, then you would subtract 180 - 90. Therefore, the remaining angle would have to be 90 degrees.

8 0
3 years ago
Determine whether the integral is convergent or divergent. [infinity] 7 e−1/x x2 dx convergent divergent Changed: Your submitted
inessss [21]

I suppose the integral could be

\displaystyle\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx

In that case, since -\frac1x\to0 as x\to\infty, we know e^{-1/x}\to1. We also have \left(e^{-1/x}\right)'=\frac{e^{-1/x}}{x^2}>0, so the integral is approach +1 from below. This tells us that, by comparison,

\displaystyle\frac{e^{-1/x}}{x^2}\le\frac1{x^2}\implies\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx\le\int_7^\infty\frac{\mathrm dx}{x^2}

and the latter integral is convergent, so this integral must converge.

To find its value, let u=-\frac1x, so that \mathrm du=\frac{\mathrm dx}{x^2}. Then the integral is equal to

\displaystyle\int_{-1/7}^0e^u\,\mathrm du=e^0-e^{-1/7}=1-\frac1{\sqrt[7]{e}}

4 0
3 years ago
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