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lukranit [14]
3 years ago
8

Which expression is equivalent to √128x^8y^3z^9? Assume x>0 and y>0.

Mathematics
2 answers:
Leno4ka [110]3 years ago
8 0

C is the correct answer :)

Firdavs [7]3 years ago
5 0

Answer:  The correct option is (C) 8x^4yz^4\sqrt{2yz}.

Step-by-step explanation: We are given to select the correct expression that is equivalent to the expression below:

E=\sqrt{128x^8y^3z^9}.

We will be using the following properties of exponents:

(i)~\sqrt a=a^\frac{1}{2},\\\\(ii)~(ab)^x=a^xb^x,\\\\(iii)~(a^x)^y=a^{x\times y}.

Since y > 0 and z > 0, so we will be considering the positive square root of y and z.

We have

E\\\\=\sqrt{128x^8y^3z^9}\\\\=(128x^8y^3z^9)^\frac{1}{2}\\\\=(128)^\frac{1}{2}(x^8)^\frac{1}{2}(y^3)^\frac{1}{2}(z^9)^\frac{1}{2}\\\\=(2\times 8^2)^\frac{1}{2}x^{8\times \frac{1}{2}}y^{3\times\frac{1}{2}}z^{9\times\frac{1}{2}}\\\\=8x^4yz^4(2yz)^\frac{1}{2}\\\\=8x^4yz^4\sqrt{2yz}.

Thus, the equivalent expression is 8x^4yz^4\sqrt{2yz}.

(C) is the correct option.

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