Answer:9
Step-by-step explanation: square root of 25 is 5 and of 16 the square root is 4 add both of them together and you get 9
W= width; L= length =w+22m; p= perimeter= 2(L+w)
1616 meters= 2 (L+w) substitute for L
1616m+ 2(w+22m+w) divide each side by 2
808m= 2w+22m subtract 22m from each side
786m=2w divide each side by 2
393m=w Anwer: The width is 393 meters
L=w+22m=393m+22m=415m Answer: The length is 415 meters
Use PEMDAS. Parenthesis, Exponents, Multiply, Divide, Addition, Subtraction.
So, you'd distribute 5 into the parenthesis, leaving you with 9+20x+20, then add like terms. 20x+29
Answer:
a = 120 cm²
Step-by-step explanation:
n = number of sides
edge length
40/n
divide the polygon into n congruent triangles
a = (1/2)(edge * apothem) * number of triangles
a = (1/2)(40/n)(6) * n
n cancels out
a = (1/2)(40)(6)
a = 120 cm²
Answer:
a)

b) 0.09
Step-by-step explanation:
We are given the following in the question:

where B(t) gives the brightness of the star at time t, where t is measured in days.
a) rate of change of the brightness after t days.

b) rate of increase after one day.
We put t = 1

The rate of increase after 1 day is 0.09