Answer
Find out the length of OP .
To prove
As given
In △JKL, JO=44 in.
Now as shown in the diagram.
JP , MK, NL be the median of the △JKL and intresection of the JP , MK, NL be O .
Thus O be the centroid of the △JKL .
The centroid divides each median in a ratio of 2:1 .
Let us assume x be the scalar multiple of the OP and JO .
As given
JO = 44 in
2x = 44
x = 22 in
Thus the length of the OP IS 22 in .
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:
B. 3
Step-by-step explanation:
The degree of this polynomial is based on the highest power on the exponents (if there is more than one variable, it is based on the sum)
The highest power is 3, so the degree is 3
Answer:
Step-by-step explanation:
Asymptotes 3
g(x) =
Factors of denominator will be,
x² - 3x - 10 = x² - 5x + 2x - 10
= x(x - 5) + 2(x - 5)
= (x + 2)(x - 5)
Therefore, factored form of g(x) will be,
g(x) =
Asymptotes 4
h(x) =
=
=
=
Answer:
30
Step-by-step explanation:
N/-2=-15
N= -15 times -2
N= 30