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ankoles [38]
3 years ago
11

The population of a colony of bacteria can be modeled by the function P(t) = 19,300(5)^t, where t is the elapsed time

Mathematics
2 answers:
kipiarov [429]3 years ago
6 0

Answer:

C. P–1(t) =   log5 (StartFraction t Over 19,300 EndFraction)

Step-by-step explanation:

allsm [11]3 years ago
4 0
Answer: root t(5)/19300

Explanation:

P(t) = 19300(5)^t
P-1(t) = root t(5)/19300


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Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
2 years ago
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
3 years ago
Find the surface area of the triangular prism please.
Kobotan [32]
Surface area =  area of 3 rectangles + 2 triangles

            =  3*(3*7) + 2 * ( 1/2 * 3 * 2.6)

            =   63 +   2* 3.9

            =   70.8  in^2

3 0
3 years ago
Define a variable, write an equation and SOLVE the equation. Sandy had
notka56 [123]
The answer is 21 because 189 divided by 9 is 21
7 0
2 years ago
Read 2 more answers
Write an inequality to describe the possible values of x.
Papessa [141]

Answer:

d

Step-by-step explanation:

x<9+7, and x+7>9

solve

x<16

x>2

2<x<16

6 0
2 years ago
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