Answer:
LEts start with 10^1
If we have positive exponent then we add zeros
10^1= 10
(Put 2 zeros because exponent is 2)
(Put 3 zeros because exponent is 3)
(Put 4 zeros because exponent is 4)
(Put 5 zeros because exponent is 5)
For negative exponent , we make a fraction . we put 1 at the top always and number as the bottom
(Put 1 zero at the bottom because exponent is -1)
(Put 2 zeros at the bottom because exponent is -2)
(Put 3 zeros at the bottom because exponent is -3)
To simplify x^2-3 =5x
You would first subtract 5x from both sides
X^3-5x-3
Next you would plug this into the quadratic equation:
X=5+/- the square root of: -5^2 -4(1)(-3)/2(1)
Then simplify,
5+/- the squareroot of 24 + 12 / 2
5+/- The squareroot of 36 /2
5+/- 6 / 2
Then solve if it’s an addition or subtract
5+6/2
X=11/2 or 5 1/2
5-6/2
X= -1/2
The answer is x=-1/2 or x=11/2
Hope this helps
The answer would be C. 1 because if you replace x in the equation with 1 and solve the equation it would be<em> </em><em>1</em>
