Question

At a certain instant, a particle is moving in the direction with momentum 18 kg·m/s. During the next 0.5 s, a constant force <-4, 12, 0> N acts on the particle. What is the momentum of the particle at the end of this 0.5 s interval?

Answer 1

Answer:

24.325 kg m/s

Explanation:

Initial momentum, pi = 18 kg m/s

F = < -4, 12, 0>

t = 0.5 s

Let the final momentum is pf.

The magnitude of force is

$F=\sqrt{(-4)^{2}+12^{2}+0^{2}}=12.65 N$

According to the Newton's second law, the rate of change of momentum is equal to the force.

$F = \frac{p_{f}-p_{1}}{t}$

$12.65= \frac{p_{f}-18}}{0.5}$

pf - 18 = 6.325

pf = 24.325 kg m/s

Thus, the momentum of body after 0.5 s is 24.325 kg m/s.