A 5 kg rock is dropped down a vertical mine shaft. How long does it take to reach the bottom, 79 meters below?
1 answer:
Answer:
The time for the rock to reach the bottom is 4.02 seconds.
Explanation:
Given;
mass of the rock, m = 5 kg
height of the rock fall, h = 79 meters
The time to drop to the given height is given by;
where;
t is the time to fall to the bottom
g is acceleration due to gravity = 9.8 m/s²
Therefore, the time for the rock to reach the bottom is 4.02 seconds.
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Answer:
236.3 x C
Explanation:
Given:
B(0)=1.60T and B(t)=-1.60T
No. of turns 'N' =100
cross-sectional area 'A'= 1.2 x m²
Resistance 'R'= 1.3Ω
According to Faraday's law, the induced emf is given by,
ℰ=-NdΦ/dt
The current given by resistance and induced emf as
I = ℰ/R
I= -NdΦ/dtR
By converting the current to differential form(the time derivative of charge), we get
= -NdΦ/dtR
dq= -N dΦ/R
The change in the flux dФ =Ф(t)-Ф(0)
therefore, dq = (Ф(0)-Ф(t))
Also, flux is equal to the magnetic field multiplied with the area of the coil
dq = NA(B(0)-B(t))/R
dq= (100)(1.2 x )(1.6+1.6)/1.3
dq= 236.3 x C