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Assoli18 [71]
3 years ago
13

The magnitude of the electric force between two protons is 2.3x10-26 n. how far apart are they?

Physics
1 answer:
Andru [333]3 years ago
6 0

To solve this problem, we make use of the Coulumb’s law which relates the electrical force to the charges. The formula used in Coulumb’s law is given as:

F = k q1 q2 / r^2

where,

F = electric force = 2.3 *  10^-26 N

k = Coulumb’s constant = 9 * 10^9 N m^2/C^2

q1 = q2 = electric charge of protons = 1.602 * 10^-19 C

r = distance between the two protons

 

Substituting the given values:

2.3 *  10^-26 N = (9 * 10^9 N m^2/C^2) (1.602 * 10^-19 C)^2 / r^2

r^2 = 0.01 m^2

r = 0.1 m

 

Therefore the protons are only 0.1 m apart or 10 cm.

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Answer:

The only incorrect statement is from student B

Explanation:

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Let's examine student claims using these rotation periods

Student A. The time for 4 turns around the sun is

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In this time I make as many rotations on itself each one with a time to = 58.7 Earth days

           #_rotaciones = t / to

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therefore this statement is TRUE

student B. the planet rotates 6 times around the Sun

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          t = 528 s

The number of rotations on itself is

           #_rotaciones = t / to

           #_rotations = 528 / 58.7

           #_rotations = 9

False, turn 9 times

Student C. 8 turns around the sun

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the number of turns on itself is

            #_rotaciones = t / to

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True

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<u>Explanation:</u>

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