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3 years ago

What are the subsets of {a, b, c}?

Mathematics

1 answer:

never [62]3 years ago

5 0

Answer:

There is a big thing that you have to use this an dyou are gloing to use a;ll the knowlige that you know and you take it and you have to use it in the sentces

Step-by-step explanation:

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A lady walks into a cafe. She order four items. a coffe for 3.28, a bagel for 1.27, a juice for 0.56 and a muffin for 2.33. How

malfutka [58]

She spent $7.44 because 3.28 + 1.27 + 0.56 + 2.33 = 7.44

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2 years ago

Sherry buys a pair of boots from Rack Room Shoes for $45.00. What is the total amount paid if

Luba_88 [7]

Answer:

Before Tax Price: $45.00

Sale Tax: 7.00% or $3.15

After Tax Price: $48.15

here u go love

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Rewrite the equation in Ax+By=C form. Use integers A, B, and C. y+5=5(x-3)

Kaylis [27]

$y+5=5(x-3)\\ y+5=5x-15\\ 5x-y=20$

4 0

4 years ago

Read 2 more answers

Find the area. Round to the nearest tenth.

motikmotik

Answer:

40m^2

Step-by-step explanation:

Hope it helps!!:)

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3 years ago

Expand (2x+2)^6 How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago