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natta225 [31]
3 years ago
5

If point A is located at (5,-7) and there are 8 points between A and B what could be the possible coordinates for point B ?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0
Just take the point (5,-7) and move it 9 points horizontally or vertically. So one point could be (14,-7)  We moved horizontally to the right.
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3 years ago
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What is the place value of 1 in 5,678.321
alukav5142 [94]
<span>The place value of 1 in 5,678.321 is one-one thousands. The one digit is the third place behind the decimal point. The first place behind the decimal point is three one-tenths. The second place behind the decimal is two one-hundredths. A decimal number is a division of one. In other words, it will take a thousand one-one thousands to equal one.</span>
6 0
4 years ago
Choose the correct answers for (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to
jekas [21]
Hi there

(a) the total installment price
93×15=1,395

(b) the carrying charges
1,395−1,250=145

(c) the number of months needed to save the money at the monthly rate to buy the item for its cash price.
1,250÷93=13

Good luck!
6 0
4 years ago
Harper knows he is 100 yards from school. The map on his phone shows that the school is 1/3 inch from his current location. If H
Anton [14]

Answer:

4 7/17 yeards or 4.412 yards approximately if the map shows the distance as 3 inches.

Step-by-step explanation:

The actual distance of the Harper from the school = 50 yards. According to the map, the distance from the school = 34 inches. We could say 34 inches represents 50 yards. So, 1 inch could be represented by 50/34 = 25/17 yards. In order to find the actual length of 3 inches in yards, we need to multiply 1 inches value of yards by 3.Therefore, 3 inches = 3* 25/17 = 75/17 = 4 7/17 yeards in decimals 4.412 yards approximately. Therefore,  Harper from home is  4 7/17 yeards or 4.412 yards approximately if the map shows the distance as 3 inches.

5 0
4 years ago
Part A: Find the LCM of 7 and 12. Show your work. (3 points)
inna [77]

Answer:

A. 84; B. 8; C. 8 × 19

Step-by-step explanation:

Part A. Least common multiple

Step 1. List the prime factors of each.

7 = 7

12 = 2 × 2 × 3

Step 2: Multiply each factor the greatest number of times it occurs in either number.

7 has one 7; 12 has two 2s and one 3.

LCM = 7 × 2 × 2 × 3

LCM = 7 × 12

LCM = 84

Part B. Highest common factor

Find all the factors of 56 and 96.

Factors of 56: 1, 2, 4,     7, 8,      14,          28

Factors of 96: 1, 2, 4, 6,     8, 12,    16, 24,     32, 48

The highest factor that in both 56 and 96 is 8.

Part C. Factoring

56 + 96 = 8(7 + 12) = 8 × 19

The GCF is 8.

19 = 7 + 12 is the sum of two numbers that do not have a common factor.

4 0
4 years ago
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