I really need help on this, I'm stuck

Which expression is equivalent to n + n - 0.18n?

horrorfan [7]

n + n - 0.18n

We can rewrite it as

2n - 0.18n

And if we solve it

(2 - 0.18)n = 1.82n

So the equivalente expression is B.

5 0

3 years ago

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What is the range of the heights of the girls?

Softa [21]

Answer:

Formula of range is HIGHEST VALUE - LOWEST VALUE....

8 0

2 years ago

My good friends,for the second time in our history,a British prime minister has returned from Germany bringing peace with honor.

satela [25.4K]

<span>C) appeasement from what it says i dunno though i just think so >.> good luck!</span>

4 0

3 years ago

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Which value of x make the equation 1.25(4x − 10) = 7.5 true?

Artemon [7]

Answer:

55.76

Step-by-step explanation:

semoga mambantu

l

7 0

3 years ago

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Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure

Marina CMI [18]

Answer:

a) $P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

b) $P(0.11 < \bar X < 0.13)$

And we can use the z score defined by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using the limits we got:

$z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22$

$z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22$

And we want to find this probability:

$P(-2.22< Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.12,0.009)$

Where $\mu=0.12$ and $\sigma=0.009$

We are interested on this probability

$P(0.11$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by: