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sleet_krkn [62]
3 years ago
6

Heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelllllllllllllllllllllllllllllllllllllllllllllllllllllllllllp!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Alex is constructing a square in which two of its vertices are points X and Y. He has already used his straightedge and compass to construct the lines and arcs shown.



What should Alex do for his next step?

A. Use a straightedge to draw a horizontal line that contains point Z.

B. Place the point of the compass on point X and draw any arc above it.

C. Use a straightedge to draw XZ¯¯¯¯¯ .

D. Place the point of the compass on point Y and draw an arc that intersects YZ¯¯¯¯¯ , using XY as the width of the opening of the compass.

Mathematics
2 answers:
MAVERICK [17]3 years ago
5 0
Did you ever get the answer 

natulia [17]3 years ago
3 0

Answer:

D. Place the point of the compass on point Y and draw an arc that intersects YZ¯¯¯¯¯ , using XY as the width of the opening of the compass.

Step-by-step explanation:

Just took the test, hope this helps

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What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
2 years ago
Keri has a spinner with sections labeled Black,
Schach [20]

Answer:

50%

Step by step explanation

100 divided by 4 is 25

Since it is both blue and black, it is doubled from 25 to 50

4 0
3 years ago
4 + -5 * -1 + 8=? <br> i need help so yeah
Natasha2012 [34]

Answer:

1

Step-by-step explanation:

4+(-5*-1)-8

4+5-8

9-8

pemdas

8 0
2 years ago
Read 2 more answers
Angle measure represented by 36.7 rotations counterclockwise
zhannawk [14.2K]

Answer:

  • 13,212° or 73.4π radians

Step-by-step explanation:

Each rotation is 360° or 2π radians. So, 36.7 rotations is ...

  36.7×360° = 13,212°

or

  36.7×2π = 73.4π radians

7 0
3 years ago
Find the surface area of the cylinder in terms of pi. 9cm and 19cm
Natali [406]

Answer:

Surface area of cylinder= 211.5π

Step-by-step explanation:

Given,

Height of cylinder = 19cm

Diameter of cylinder = 9cm

i.e Radius of cylinder = diameter/2 = 9/2 = 4.5cm

Surface area of cylinder = 2πrh + 2πr²

Plug corresponding values of r and h in surface are formula.

Surface area of cylinder = 2πrh + 2πr² = 2π*4.5*19 + 2π*4.5²

Surface area of cylinder = 171π+40.5π = 211.5π

Hence we get surface area of cylinder= 211.5π


3 0
3 years ago
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