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sergey [27]
2 years ago
11

Solving systems of equations with substitution: y= 2x-4 y= -x+5help please!

Mathematics
1 answer:
Furkat [3]2 years ago
4 0
<span>y= 2x-4 
y= -x+5
so

</span><span>2x-4 = -x+5
2x +x = 5 +4
3x = 9
x =3

y = 2x-4
y =2(3) - 4
y = 6-4
y = 2

answer: (3,2)</span>
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Number 15. Find the equation of the line that passes through (3,-1) and is perpendicular to the line that passes through (-5, 2)
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For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1

So we first need to find the slope of the reference line.

m=(y2-y1)/(x2-x1)=(7-2)/(-1--5)=5/4

So the perpendicular line will have a slope of:

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So our perpendicular line so far is:

y=-4x/5+b, now we can use point (3,-1) to solve for the y-intercept, "b"

-1=-4(3)/5+b

-1=-12/5+b

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So the line is:

y=-4x/5+7/5 or more neatly

y=(-4x+7)/5

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Answer:

The first one

Step-by-step explanation:

The number line is supposed to show the product of 2 and five, the arrow will start at 0 because 5 times 0 is 0 then it will go to 5 because 5 times 1 is 5, then another arrow will start at 5 and point at 10 because 5 times 2 is 10

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