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Ymorist [56]
3 years ago
10

A student obtains a mixture of the chlorides of two unknown metals, X and Z. The percent by mass of X and the percent by mass of

Z in the mixture is known. Which of the following additional information is most helpful in calculating the mole percent of XCl(s) and of ZCl(s) in the mixture:________.
a) the number of isotopes of Cl
b) the Molar masses of Z and X
c) The density of either XCL(s) or ZCl(s)
d) The eprcent by mass of Cl in the mixture
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

<u>Answer:</u> The additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

<u>Explanation:</u>

To calculate the mole percent of a substance, we use the equation:

\text{Mole percent of a substance}=\frac{\text{Moles of a substance}}{\text{Total moles}}\times 100

Mass percent means that the mass of a substance is present in 100 grams of mixture

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We require the molar masses of Z and X to calculate the mole percent of Z and X respectively

Hence, the additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

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2 years ago
Use kinetic molecular theory to explain why a gas takes the shape and volume of its container
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3 years ago
If a liquid substance is transferred to a different container, what can be predicted about the volume of the liquid in the new c
taurus [48]

The same

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If a liquid substance is transferred to a different container, the volume of the liquid in the new container will remain the same.

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8 0
2 years ago
1. What is the molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution.
LenaWriter [7]

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

4 0
3 years ago
A certain man needed 400N of force to pull a load through a distance of 150cm in 8s . Calculatell i) the work done by man ii) th
Igoryamba

Answer:

a) 600 J

b) 75 W

Explanation:

Force= 400 N, distance = 150 cm = 1.5 m, time= 8s

a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W

5 0
2 years ago
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